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#2

Hello,

For part a you have the equation for the velocity of the particle when t = 5. If you integrate this in terms of t you have the equation for the displacement of the particle, so just plug t = 5 into this.

For part b, you want to work out the displacement of the particle in the next second. You need to use the second equation for this, as the first is not true for t > 5. If you integrate this equation, then plug in t = 1 you have worked out the displacement of the particle in the next second. Add your answer from part a to this and you have worked out the total displacement from 0 to 6s.

Hope this made sense!

For part a you have the equation for the velocity of the particle when t = 5. If you integrate this in terms of t you have the equation for the displacement of the particle, so just plug t = 5 into this.

For part b, you want to work out the displacement of the particle in the next second. You need to use the second equation for this, as the first is not true for t > 5. If you integrate this equation, then plug in t = 1 you have worked out the displacement of the particle in the next second. Add your answer from part a to this and you have worked out the total displacement from 0 to 6s.

Hope this made sense!

Last edited by awc14; 1 week ago

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#3

(Original post by

Hello,

For part a you have the equation for the velocity of the particle when t = 5. If you differentiate this in terms of t you have the equation for the displacement of the particle, so just plug t = 5 into this.

For part b, you want to work out the displacement of the particle in the next second. You need to use the second equation for this, as the first is not true for t > 5. If you differentiate this equation, then plug in t = 1 you have worked out the displacement of the particle in the next second. Add your answer from part a to this and you have worked out the total displacement from 0 to 6s.

Hope this made sense!

**awc14**)Hello,

For part a you have the equation for the velocity of the particle when t = 5. If you differentiate this in terms of t you have the equation for the displacement of the particle, so just plug t = 5 into this.

For part b, you want to work out the displacement of the particle in the next second. You need to use the second equation for this, as the first is not true for t > 5. If you differentiate this equation, then plug in t = 1 you have worked out the displacement of the particle in the next second. Add your answer from part a to this and you have worked out the total displacement from 0 to 6s.

Hope this made sense!

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#4

(Original post by

^^^ This, but integrate rather than differentiate.

**mqb2766**)^^^ This, but integrate rather than differentiate.

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(Original post by

Hello,

For part a you have the equation for the velocity of the particle when t = 5. If you integrate this in terms of t you have the equation for the displacement of the particle, so just plug t = 5 into this.

For part b, you want to work out the displacement of the particle in the next second. You need to use the second equation for this, as the first is not true for t > 5. If you integrate this equation, then plug in t = 1 you have worked out the displacement of the particle in the next second. Add your answer from part a to this and you have worked out the total displacement from 0 to 6s.

Hope this made sense!

**awc14**)Hello,

For part a you have the equation for the velocity of the particle when t = 5. If you integrate this in terms of t you have the equation for the displacement of the particle, so just plug t = 5 into this.

For part b, you want to work out the displacement of the particle in the next second. You need to use the second equation for this, as the first is not true for t > 5. If you integrate this equation, then plug in t = 1 you have worked out the displacement of the particle in the next second. Add your answer from part a to this and you have worked out the total displacement from 0 to 6s.

Hope this made sense!

I got 76.6m for part a. Is that right?

For part b, I'm not sure what to sub in (t=?) to find C in the second equation.

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#6

(Original post by

hello,

I got 76.6m for part a. Is that right?

For part b, I'm not sure what to sub in (t=?) to find C in the second equation.

**josefgas5**)hello,

I got 76.6m for part a. Is that right?

For part b, I'm not sure what to sub in (t=?) to find C in the second equation.

https://www.wolframalpha.com/input/?...29+from+0+to+5

b) when t=5, the curves must join so s=76.6. which gives C

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(Original post by

a) looks good

https://www.wolframalpha.com/input/?...29+from+0+to+5

b) when t=5, the curves must join so s=76.6. which gives C

**mqb2766**)a) looks good

https://www.wolframalpha.com/input/?...29+from+0+to+5

b) when t=5, the curves must join so s=76.6. which gives C

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#8

(Original post by

I got 109.9m for the final displacement. Can anyone confirm if its correct or not? Thanks

**josefgas5**)I got 109.9m for the final displacement. Can anyone confirm if its correct or not? Thanks

You can use "learn" to use it, it is quite simple and useful.

You obviously add C to that.

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(Original post by

https://www.wolframalpha.com/input/?...E2+from+5+to+6

You can use "learn" to use it, it is quite simple and useful.

You obviously add C to that.

**mqb2766**)https://www.wolframalpha.com/input/?...E2+from+5+to+6

You can use "learn" to use it, it is quite simple and useful.

You obviously add C to that.

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